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How can i reorder NxM matrix into a 1D array

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Matthew
Matthew 2018-6-12
评论： Stephen23 2018-6-12
I am looking to take a sample matrix below. The matrix will be large and looking for fast and non looping solution. Thank you.
a=[1 2 3;4 5 6;7 8 9];
reshape it into:
b=[7 8 9 4 5 6 1 2 3];
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Matthew
Matthew 2018-6-12
No the matrix is not always 3 rows. It will likely be much more in both rows and columns.

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采纳的回答

Star Strider
Star Strider 2018-6-12
Using the reshape (link) function:
b = reshape(a([3 2 1],:)', 1, [])
b =
7 8 9 4 5 6 1 2 3

更多回答（1 个）

Alfonso
Alfonso 2018-6-12
Without looping you can do:
b = [a(end,:), a(end-1,:), a(end-2,:)]; % 1D array
b =
7 8 9 4 5 6 1 2 3
You can repeat the iterations as many rows you have: [a(end-1,:), ... ,a(end-50,:)]

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