How can i reorder NxM matrix into a 1D array
1 次查看(过去 30 天)
显示 更早的评论
I am looking to take a sample matrix below. The matrix will be large and looking for fast and non looping solution. Thank you.
a=[1 2 3;4 5 6;7 8 9];
reshape it into:
b=[7 8 9 4 5 6 1 2 3];
采纳的回答
Star Strider
2018-6-12
b = reshape(a([3 2 1],:)', 1, [])
b =
7 8 9 4 5 6 1 2 3
1 个评论
Stephen23
2018-6-12
Or generalized for any number of rows:
reshape(a(end:-1:1,:).', 1, [])
更多回答(1 个)
Alfonso
2018-6-12
Without looping you can do:
b = [a(end,:), a(end-1,:), a(end-2,:)]; % 1D array
b =
7 8 9 4 5 6 1 2 3
You can repeat the iterations as many rows you have: [a(end-1,:), ... ,a(end-50,:)]
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!