Singular Jacobian with BVP4c used to solve eigenvalue problem
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I have been trying to solve an eigenvalue problem of the form:
y"+y/x+(Lambda^2)*(1-x^2)y=0
which is a Sturm-Liouville problem that occurs e.g. in the case of heat convection in tubes and channels. The task here is to find the eigenvalues Lambda in order to describe the temperature in the fluid.
As I understand one way to solve this problem is by intorudcing the parameter Lambda into the definition of the differential equation:
function dydx=evp1(x,y,lambda);
dydx=[y(2)
-y(2)/x-lambda*(1-x^2)*y(1)];
end
function res=evp1bc1(ya,yb,lambda);
res=[ya(1)-1;yb(1);ya(2)];
end
function v=evp1Guess1(x);
v=[cos(x);sin(x)];
end
clear all; close all; echo on; format long;
a=0; b=1; N=10; lambda=0.5;
solInit1=bvpinit(linspace(a,b,N),@evp1Guess1,lambda);
solN1=bvp4c(@evp1,@evp1bc1,solInit1);
This short and elegant code by Zaitsev (in the Book: Handbook of Ordinary DIfferential Equations) finds the eigenvalues for simpler eigenvalue problems (e.g. y"+Lambda.y=0). However, for my problem it creates an error message referring to a singular Jacobian which I assume is due to the presence of the y(1)/x term in the equation at x=0. Is there a way to get around this problem?
3 个评论
Tanya Sharma
2019-12-4
Hello Saeid,
Actually finding the eigenvalues is very important in my analysis. Can you share the structure of the loop for your guess vector. It may help me as I am stuck with only one eigenvalue.
Thanks in advance.
采纳的回答
Torsten
2018-6-18
Use a=(a small value) instead of a=0.
Best wishes
Torsten.
1 个评论
Merrill Yeung
2022-2-3
This simple example illustrates how to solve a BVP with an unkown parameter (here actually is an eigenvalue problem). Usually for a 2rd order ODE, only two boundary conditions are avalable. My question is how to use bvp4v to solve problems like that. (This example needs 3 boundary conditions.)
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