Divide points according to quadrant system
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I have written a code to divide L pairs (coordinates) according to 4 quadrants:
L=input('Enter the number of pairs: ');
tr=randi(10,L,2);
xy=sortrows(tr);
a=1;
b=1;
c=1;
d=1;
for ii=1:10
if xy(ii,1)<=5 && xy(ii,2)<=5
xy1(a,:)=xy(ii,:);
a=a+1;
elseif xy(ii,1)>5 && xy(ii,1)<11 && xy(ii,2)<=5
xy2(b,:)=xy(ii,:);
b=b+1;
elseif xy(ii,1)>5 && xy(ii,1)<11 && xy(ii,2)>5 && xy(ii,2)<11
xy3(c,:)=xy(ii,:);
c=c+1;
elseif xy(ii,1)<=5 && xy(ii,2)>5 && xy(ii,2)<11
xy4(d,:)=xy(ii,:);
d=d+1;
end
end
There is a main array xy(Lx2) which takes random integer pairs and then divides them into 4 more additional arrays: xy1, xy2, xy3, xy4. The 2 dividing lines are x=5 and y=5. Starting from bottom-left and going in anticlockwise direction to top left.
2 个评论
Rik
2018-6-17
What is exactly your question? Would you like to know how to un-loop this? Or how to make it more adaptable to different division lines?
Vatsal Gupta
2018-6-18
This is the quadrant system I'm referring to. xy will 'L' contain coordinate point pairs and these points will be divided into 4 arrays xy1 (I), xy2(II), xy3(III), and xy4(IV).
采纳的回答
Rik
2018-6-18
You still haven't explained what your question is, so I'm going to assume you want to un-loop this. The code below yields the same results as yours, but does it without a loop (and won't result in an error for L<10).
L=input('Enter the number of pairs: ');
tr=randi(10,L,2);
xy=sortrows(tr);
index1=xy(:,1)<=5 & xy(:,2)<=5;
xy1=xy(index1,:);
a=size(xy1,1);
index2=xy(:,1)>5 & xy(:,1)<11 & xy(:,2)<=5;
xy2=xy(index2,:);
b=size(xy2,1);
index3=xy(:,1)>5 & xy(:,1)<11 & xy(:,2)>5 & xy(:,2)<11;
xy3=xy(index3,:);
c=size(xy3,1);
index4=xy(:,1)<=5 & xy(:,2)>5 & xy(:,2)<11;
xy4=xy(index4,:);
d=size(xy4,1);
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