How to replace half the number of specific element in an array?
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Hello every one,
I have a row vector having 8236 columns, out of which 863 columns have a value 4. I want to replace 431 of the columns by a value 2. For simplicity, I am giving a vector having only 23 columns
A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4]
Here, in this vector, there are 12 columns having a value 4. How to replace half the columns by a value 2?
Any help will be appreciated.
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采纳的回答
  Stephen23
      
      
 2018-6-18
        
      编辑:Stephen23
      
      
 2018-6-18
  
      To change random columns:
>> A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4]
A =
   1   2   3   4   4   1   2   4   4   3   4   4   4   2   1   3   4   4   4   2   1   4   4
>> nnz(A==4)
ans =  12
>> idx = find(A==4);
>> num = numel(idx);
>> A(idx(randperm(num,ceil(num/2)))) = 2
A =
   1   2   3   2   2   1   2   4   4   3   2   4   2   2   1   3   2   4   4   2   1   2   4
>> nnz(A==4)
ans =  6
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更多回答(2 个)
  KALYAN ACHARJYA
      
      
 2018-6-18
        
      编辑:KALYAN ACHARJYA
      
      
 2018-6-18
  
      A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4];
for i=1:length(A)/2;
 if A(i)==4
    A(i)=2;
    end
end
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  Ameer Hamza
      
      
 2018-6-18
        
      编辑:Ameer Hamza
      
      
 2018-6-18
  
      Here is one possible solution
A=[1 2 3 4 4 1 2 4 4 3 4 4 4 2 1 3 4 4 4 2 1 4 4];
index = find(A==4);
randomIndex = randperm(length(index));
A(index(randomIndex(1:end/2))) = 2;
it will randomly select which columns to change.
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