How do i do this

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Hunter Herrenkohl
Hunter Herrenkohl 2018-6-18
评论： Hunter Herrenkohl 2018-6-18
I have
R = input('Please enter a number of rows for the matrix')
C = input('Please enter a number of columns for the matrix')
M = randi(2, R, C)
for M2 = 1:numel(M)
if M(M2) > 1
M(M2) = -1
end
end
M3 = M
for MN = 1:numel(M3)
I need to: Part c: You will need to use a loop to check the neighbors of each element and then count how many agree with the current element you are on. You will need to check the elements to the left, right, above and below. You will probably need to create another matrix to keep track of the similar spin count.
How do i do this?
  2 个评论
John D'Errico
John D'Errico 2018-6-18
Define "agree". Is that a synonym for "is the same as" or "isequal to"?
Hunter Herrenkohl
Hunter Herrenkohl 2018-6-18
equal to, i have a RxC matrix (the dimensions indicated from the user) filled with 1s and -1s. I have to find out how many are equal to their neighbors and how many of their neighbors they are equal to in order to figure out if they will change or not

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采纳的回答

Ankita Bansal
Ankita Bansal 2018-6-18
Hi, I am assuming that you are trying to compare M3(i,j) with it's adjacent elements and you want to store the number of times M3(i,j) matches with adjacent elements in a new variable c(i,j). You can do this by creating a new matrix of size (R+2,C+2).
R = input('Please enter a number of rows for the matrix');
C = input('Please enter a number of columns for the matrix');
M = randi(2, R, C);
M(M>1)=-1; % instead of "for M2 = 1:numel(M) if M(M2) > 1 M(M2) = -1 end end"
M3 = M;
M4=NaN(R+2,C+2);
M4(2:end-1,2:end-1)=M3;
c=zeros(R,C);
for i = 2:R+1
for j=2:C+1
arr = [M4(i-1,j) M4(i+1,j) M4(i,j+1) M4(i,j-1)];
c(i-1,j-1)=nnz(ismember(arr,M4(i,j)));
end
end

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