Line orientation in 3D from centroid and Euler angles

5 次查看(过去 30 天)
I used the regionprops3 function to detect centroid and Euler angles of cylinders of the same size in 3D space. Now I want to obtain the 3D coordinates of a line (of given length, representing the axis of the cylinders) passing through the centroid and oriented according to the three Euler angles. What kind of coordinate transformation should I consider?

采纳的回答

Matt J
Matt J 2018-6-19
编辑:Matt J 2018-6-19
I think you'd be better off using regionprops3 to extract the Eigenvalues and Eigenvectors properties of the cylinders, instead of the Orientation property (which I assume you are using now). The eigenvector corresponding to the largest eigenvalue should give you the direction vector of the long axis of the cylinder directly.
  5 个评论
Matt J
Matt J 2018-6-19
编辑:Matt J 2018-6-19
Well, as I said, the eigenvector corresponding to the largest eigenvalue is the direction vector. So, you have it already from
regionprops3(yourImage, 'Centroid','EigenVectors','EigenValues')
One thing to note. I believe the EigenVectors are the rows of the matrix given in the output of regionprops3, not the columns.
Saurabh Patel
Saurabh Patel 2018-9-20
I think eigenvectors are still the columns of eigenvector matrix but they are in image coordinates i.e. (row,col,page) and not in (x,y,z).
For (x,y,z) space, I think we need to represent it as {eigenvector(2,1), eigenvector(1,1), eigenvector(3,1)} for the major principal direction.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Linear Algebra 的更多信息

产品


版本

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by