Line orientation in 3D from centroid and Euler angles
15 次查看(过去 30 天)
显示 更早的评论
I used the regionprops3 function to detect centroid and Euler angles of cylinders of the same size in 3D space. Now I want to obtain the 3D coordinates of a line (of given length, representing the axis of the cylinders) passing through the centroid and oriented according to the three Euler angles. What kind of coordinate transformation should I consider?
0 个评论
采纳的回答
Matt J
2018-6-19
编辑:Matt J
2018-6-19
I think you'd be better off using regionprops3 to extract the Eigenvalues and Eigenvectors properties of the cylinders, instead of the Orientation property (which I assume you are using now). The eigenvector corresponding to the largest eigenvalue should give you the direction vector of the long axis of the cylinder directly.
5 个评论
Matt J
2018-6-19
编辑:Matt J
2018-6-19
Well, as I said, the eigenvector corresponding to the largest eigenvalue is the direction vector. So, you have it already from
regionprops3(yourImage, 'Centroid','EigenVectors','EigenValues')
One thing to note. I believe the EigenVectors are the rows of the matrix given in the output of regionprops3, not the columns.
Saurabh Patel
2018-9-20
I think eigenvectors are still the columns of eigenvector matrix but they are in image coordinates i.e. (row,col,page) and not in (x,y,z).
For (x,y,z) space, I think we need to represent it as {eigenvector(2,1), eigenvector(1,1), eigenvector(3,1)} for the major principal direction.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrix Computations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!