not-a-knot spline
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i need to calculate the value of the cubic spline not a knot in the point x=1.97, the problem gives me coordinates of x=[0.0 0.5 1.0 1.5 2.0] and the function y=(sin(x)-(x+1).^2)/(x.^2+3). i don't understand why sometimes when i do y=f(x) it gives me a vector and sometimes like now it gives me only a value, and as a result it gives me an error when calculating the spline.
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KSSV
2018-6-20
x=[0.0 0.5 1.0 1.5 2.0] ;
y = @(x) (sin(x)-(x+1).^2)./(x.^2+3) ;
y = y(x) ;
xi = 1.97 ;
yi = interp1(x,y,xi,'spline')
plot(x,y,'b')
hold on
plot(xi,yi,'*r')
2 个评论
Gianluca Manissero
2018-6-20
Kaloyan Pavlov
2020-12-8
Sorry I dont understand, if you have the function why not just calculate the function with x = 1.97?
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