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NaN and Inf error when using "fit"

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J.S.
J.S. 2018-6-20
评论： J.S. 2018-6-21
Does anyone know why this error occurs when "fit" is called? My data contain no NaN or Inf.
Warning: NaN, Inf, or complex value detected in startpoint; choosing random starting point instead. > In curvefit.attention.Warning/throw (line 30) In fit>iFit (line 299) In fit (line 108) In MyCode (line 47) >>
  2 个评论
J.S.
J.S. 2018-6-21
Danke, Stephan. Ja, der Anfangspunkt wurde von MATLAB bestimmt. Um dieses Problem zu vermeiden habe ich in Zukunft vor, ihn selber zu bestimmen.
Gruesse
J.S.

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回答（1 个）

Jos (10584)
Jos (10584) 2018-6-21
Are you really sure?
Set a breakpoint in line 47 of your function MyCode, and check the values you enter into fit ...

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