How to interpolate intermediate values?
显示 更早的评论
I have an array with 110 values. let say:
M1_allvalues = [1,2,10,-1,-2,..,-10, 1, 2..........,10]
I simply want to make the array to a size of 3600 values in it, by interpolating the values in between each array element. There would be approximately 32-33 values between each element to achieve 3600 values array. For example:
Between 1 and 2 in the given array some 32 values, then the beginning would be:
newArray = [1, 1.03, 1.06, 1.09........,1.97, 2,......, 3,........, 110]
How do I do that? I was thinking of this:
for i=1:length(M1_allvalues) - 1
newArray(i,1)= M1_allvalues(i,1): (32-33 vales): M1_allvalues(i + 1,1);
end
could you me some idea?
2 个评论
Walter Roberson
2018-6-21
Is it required that the existing elements all appear in the output exactly? If equal spacing were used then some elements might only be approximated.
采纳的回答
% M1_allvalues = [1,2,3,....,110] ;
iwant = linspace(min(M1_allvalues),max(M1_allvalues ),3600) ;
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Translated by 
