Find the number of times a number is in an array for every column

1 次查看（过去 30 天）
NMans
NMans 2018-6-21
回答： Fangjun Jiang 2018-6-21
Hi, this is probably quite simple but can't get my head around it. I have 8784 x 9 matrix and I want to find value <= 0 in this matrix for each column and save the answer as a new matrix of 1 x 9. I've started with this:
[nrow, ncol] = size (matrix)
for k = 1:ncol
newMatrix = find(matrix =>0)
end
This ends up giving me just 1 column instead of 9 columns. Eventually I want to use the number of times the value of 0 (or less) occurs in each column as part of my next calculation. Can anybody help? Thanks!

请先登录，再回答此问题。

采纳的回答

Fangjun Jiang
Fangjun Jiang 2018-6-21
Hope this give you a clue
a=rand(3,9)-0.5;
b=a<=0;
c=sum(b)

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by