how i can perform this for loop
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Hello im trying to perform this cod 20 times but the for loop moves one time"j=1 instead of 20" could anyone please help me to solve it!
clear all
close all
clc
for j=1:20
c=[1 2 3 5 6 7 8 99 9 3 4 55 66 7 8 9 9 97 0 1 2 ];
for k=1:length(c)
if c(k)>=5
ag(k)=1
k1=k
return
elseif c(k)<=-1
ag(k)=0
k1=k;
return
else
end
end
m=k1
l(j)=sum(ag)
end
j
2 个评论
Stephen23
2018-6-22
"Hello im trying to perform this cod 20 times but the for loop moves one time j=1 instead of 20"
Because that is exactly what you wrote your code to do. On the first loop iteration, where j=1, it reaches the inner loop. The inner loop iterates four times until the first if condition is true (because c(4)==5) upon which you call return. The end.
The return help describes clearly that it returns to the calling function or the command window. And your code clearly run the inner loop until k=4 and so the first condition is true and so you call return, which ends the evaluation of your code. That is what you wrote the code to do, so that is what it does.
Hint: instead of guessing what MATLAB functions and commands do, read their help and try their examples.
Tammun filistin
2018-6-22
编辑：Tammun filistin
2018-6-22
采纳的回答
Pieter Hamming
2018-6-22
0 个投票
Replace "return" by "continue". "Return" stops the whole file, "continue" sends it on to the next iteration in the for loop.
1 个评论
Tammun filistin
2018-6-22
编辑：Tammun filistin
2018-6-22
更多回答（1 个）
Meade
2018-6-22
You're using the return function.
This exits out of the j loop. Try instead replacing return with continue. I'm able to get j to iterate to 20 with that small change.
Best, Meade
clear all
close all
clc
for j=1:20
c=[1 2 3 5 6 7 8 99 9 3 4 55 66 7 8 9 9 97 0 1 2 ];
for k=1:length(c)
if c(k)>=5
ag(k)=1
k1=k
continue
elseif c(k)<=-1
ag(k)=0
k1=k;
continue
else
end
end
m=k1
l(j)=sum(ag)
end
j
%% 20th iter
ag =
0 0 0 1 1 1 1 1 1 0 0 1 1 1 1 1 1 1
k1 =
18
m =
18
l =
13 13 13 13 13 13 13 13 13 13 13 13 13 13 13 13 13 13 13 13
j =
20
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