Runge-Kutta - Plot Graphic - Help
显示 更早的评论
Hey guys! I wrote a code to study the dynamic of some parameters in a reactor. The problem is that I applied RK, but one of the variables is an explicit equation and, therefore, I'm having trouble to figure it out how to plot the graphic of Tcw2. Can somebody give me an idea? I need Tcw2 versus t (time).....
Thank you! Best regards!
function dx=EstudoDeCaso_RK4(t,x)
%Legenda
%x(1) ---> V
%x(2) ---> h
%x(3) ---> Ca
%x(4) ---> Cb
%x(5) ---> Cc
%x(6) ---> Cd
%x(7) ---> Cw
%x(8) ---> Tr
%Parâmetros
Vu=4; %m³
d=(2*Vu/pi)^(1/3); %m
H=2*d; %m
A=pi*d^2/4; %m²
Vo=0.2; %m³
ve=0.004; %m³/s
Cwe=55; %kmol/m³
Cbe=1; %kmol/m³
Fbe=Cbe*ve*1000; %mol/s
MMa=88/1000; %kg/mol
MMw=18/1000; %kg/mol
MMb=40/1000; %kg/mol
MMmist=(Cbe/(Cbe+Cwe)*MMb+Cwe/(Cbe+Cwe)*MMw); %kg/mol
Cp=75.24; %J/(kmol.K)
Cpa=170.7; %J/(kmol.K)
theta_w=Cwe/Cbe; %(-)
UA=3000; %J/(s.K)
To=300; %K
Tref=273; %K
Tcw1=285; %K
mcw=100; %kg/s
dH=-7.9076E+07; %J/kmol
ko=0.39175; %m³/(kmol.s)
E=5472.7; %K^-1 ----> Ea/R
%Equações Explícitas
Na=x(3)*x(1);
Nb=x(4)*x(1);
Nc=x(5)*x(1);
Nd=x(6)*x(1);
Nw=x(7)*x(1);
NCp=Cp*(Nb+Nc+Nd+Nw)+Cpa*Na;
kd=ko*exp(E*(1/273-1/x(8)));
Kc=10^(3885.44/x(8));
ra=kd*(x(5)*x(6)/Kc-x(3)*x(4));
rb=ra;
rc=kd*(x(3)*x(4)-x(5)*x(6)/Kc);
rd=rc;
Tcw2=x(8)-(x(8)-Tcw1)*exp(-UA/(mcw*Cp));
Qdot=mcw*Cp*(Tcw1-x(8))*(1-exp(-UA/(mcw*Cp)));
%Equações Diferenciais
dx(1)=ve;
dx(2)=ve/A;
dx(3)=ra-ve/x(1)*x(3);
dx(4)=rb+ve/x(1)*(Cbe-x(4));
dx(5)=rc-ve/x(1)*x(5);
dx(6)=rd-ve/x(1)*x(6);
dx(7)=ve/x(1)*(Cwe-x(7));
dx(8)=(Qdot-Fbe*Cp*(1+theta_w)*(x(8)-To)-ra*x(1)*dH)/NCp;
%Vetor linha em vetor coluna
dx=dx';
end
回答(1 个)
Torsten
2018-6-27
1 个投票
Can you plot Tr versus t ?
Then you should also be able to plot
Tr-(Tr-Tcw1)*exp(-UA/(mcw*Cp))
versus t.
Best wishes
Torsten.
类别
在 帮助中心 和 File Exchange 中查找有关 Graphics Objects 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!