How to remove a row from the table?

Question

Aswin Sandirakumaran 2018-6-27

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/407679-how-to-remove-a-row-from-the-table

评论： Aswin Sandirakumaran 2018-6-27

Gv = graph({'s1' 's_1' 's2' 's_2' },{'s2' 's_2','s3' 's_3'});
figure(1)
hold on
Gv.Nodes.Availability = {'null','null','null','null','null','null'}';
Gv.Nodes.Memory = [8,6,7,8,6,7]';
%Gv.Nodes.Bandwidth = [3,2,3,2,3,2]';
title('Graph representing Services & VLs');
plot(Gv);
Application = table(Gv.Nodes);  % table containing the info of apps
disp(Application);
hold off

Output: Gives me a table with Name, Availability and Memory

             Var1              
    Name     Availability    Memory
    _______________________________
    's1'        'null'         8   
    's2'        'null'         6   
    's_1'       'null'         7   
    's_2'       'null'         8   
    's3'        'null'         6   
    's_3'       'null'         7

How to Remove a row from the table: say how to remove s1 from the existing table?

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Image Analyst 2018-6-27

This code produces a table of tables:

and each of the 6 tables has only one row.

I don't know how to answer you. Perhaps you want to reword your question, or your code.

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Answer 1

Adam Danz 2018-6-27

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/407679-how-to-remove-a-row-from-the-table#answer_326517

编辑：Adam Danz 2018-6-27

在 MATLAB Online 中打开

To remove row 1 from the table 'Application' :

Application(1,:) = []

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Adam Danz 2018-6-27

编辑：Adam Danz 2018-6-27

在 MATLAB Online 中打开

First, I think you should read the comment from @Image Analyst because your table is actually a table of tables. I'm not sure what you want to do with s1 in your table.

If extracting it means isolating the s1 sub-table and storing it in another variable,

s1 = Application(1,1);

If you'd like to extract and store the 's1' from the sub-table,

s1 = Application{1,1}(1,1);

If you're trying to remove the entire s1 sub-table you can use the code I already shared above. If you're trying to remove the 's1' from the sub-table but keep the rest of that 'row' in the main table,

Application{1,1}(1,1) = table({''});

Note, you can only replace the 's1' with an empty string or {[]}. But more importantly, the table-of-tables isn't a good practice. Why do you need to assign Gv.Nodes to a new table in the first place? Why not just rename it?

Application = Gv.Nodes;

Now it's much simpler and cleaner to 'remove' (replace) 's1':

Application(1,1) = {''};

Aswin Sandirakumaran 2018-6-27