Hi!.Can anyone please help me how to get rid of this errors.I herby attach my code and the errors.

Question

Sanjal C C 2018-6-29

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/408121-hi-can-anyone-please-help-me-how-to-get-rid-of-this-errors-i-herby-attach-my-code-and-the-errors

评论： Joe Jones 2022-7-12

function [xfar_in,yfar_in] = fartheta(y_veh, x_veh)
  % c=0.0100;
  % error_in=0;
  % amplitude=1;
  % xfar_in=zeros(2,1);
  % yfar_in=zeros(2,1);
  % xin_new=zeros(2,1);
  % yin_new=zeros(2,1);
  % slope_in=zeros(2,1);
  % slope_curve_in=zeros(2,1);
  x_save = zeros(2,1);
  y_save = zeros(2,1);
  % coder.varsize('x_save',[1, 2 * length(x_veh)]);
  % coder.varsize('y_save',[1, 2 * length(y_veh)]);
  % error_in = 0.001;
  % xin_new = x_veh;
  % yin_new = y_veh;
  for i = 1:length(x_veh)
    xin_new = x_veh(i);
    yin_new = y_veh(i);
    error_in = 0.001;
    while error_in>=0
      xin_new = xin_new + 0.01;
      yin_new = 1*sin(2*pi*xin_new/25);
      slope_in = (yin_new-y_veh)/(xin_new-x_veh);
      slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
      error_in = slope_curve_in-slope_in;
      xin_new = xin_new+0.01;
    end
    x_save = [x_save;xin_new];
    y_save = [y_save;yin_new];
  end
  xfar_in = x_save;
  yfar_in = y_save;
  % xfar_in = xin_new;
  % yfar_in = yin_new;
  % d_in = sqrt(((x_veh-xfar_in)^2) + ((y_veh-yfar_in)^2));
  %  
  % m1=tan(hdg);
  % m2=(y_veh-yfar_in)/(x_veh-xfar_in);
  % farangle=atan((m1-m2)/(1+m1*m2));

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Joe Jones 2022-7-12

Dear

Did you solve this problem ?

I also had this problem recently. "An error occurred while propagating data type 'double' through 'adrc/cg_adrc'". (the last problem in the attached picture 'erroes.JPG')

Hope you can help me if possible. Thank you.

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Answer 1

Walter Roberson 2018-6-30

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https://ww2.mathworks.cn/matlabcentral/answers/408121-hi-can-anyone-please-help-me-how-to-get-rid-of-this-errors-i-herby-attach-my-code-and-the-errors#answer_326971

You need to preallocate the output variable and assign into the appropriate locations in it, instead of dynamically growing your array.

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Sanjal C C 2018-6-30

编辑：Walter Roberson 2018-6-30

在 MATLAB Online 中打开

function [xfar_in,yfar_in] = fartheta(y_veh, x_veh)
  % c=0.0100;
  % error_in=0;
  % amplitude=1;
  % xfar_in=zeros(2,1);
  % yfar_in=zeros(2,1);
  % xin_new=zeros(2,1);
  % yin_new=zeros(2,1);
  % slope_in=zeros(2,1);
  % slope_curve_in=zeros(2,1);
  x_save = zeros(2,1);
  y_save = zeros(2,1);
  % coder.varsize('x_save',[1, 2 * length(x_veh)]);
  % coder.varsize('y_save',[1, 2 * length(y_veh)]);
  % error_in = 0.001;
  % xin_new = x_veh;
  % yin_new = y_veh;
  for i = 1:length(x_veh)
    xin_new = x_veh(i);
    yin_new = y_veh(i);
    error_in = 0.001;
    while error_in>=0
      xin_new = xin_new + 0.01;
      yin_new = 1*sin(2*pi*xin_new/25);
      slope_in = (yin_new-y_veh)/(xin_new-x_veh);
      slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
      error_in = slope_curve_in-slope_in;
      xin_new = xin_new+0.01;
    end
    x_save = [x_save;xin_new];
    y_save = [y_save;yin_new];
  end
  xfar_in = x_save;
  yfar_in = y_save;
  % xfar_in = xin_new;
  % yfar_in = yin_new;
  % d_in = sqrt(((x_veh-xfar_in)^2) + ((y_veh-yfar_in)^2));
  %  
  % m1=tan(hdg);
  % m2=(y_veh-yfar_in)/(x_veh-xfar_in);
  % farangle=atan((m1-m2)/(1+m1*m2));

both the inputs are of size [2 1] and I should get two outputs of [2 1] each.The outputs are obtained when the while loop condition values are false .Their is problem is in declaration.

Sanjal C C 2018-6-30

编辑：Walter Roberson 2018-6-30

在 MATLAB Online 中打开

function [xfar_in,yfar_in] = fartheta(y_veh,x_veh,error_in)
% c=0.0100;
% error_in=0;
% amplitude=1;
% xfar_in=zeros(2,1);
% yfar_in=zeros(2,1);
% xin_new=zeros(2,1);
% yin_new=zeros(2,1);
% slope_in=zeros(2,1);
% slope_curve_in=zeros(2,1);
x_save = zeros(2,1);
y_save = zeros(2,1);
% coder.varsize('x_save',[1, 2 * length(x_veh)]);
% coder.varsize('y_save',[1, 2 * length(y_veh)]);
% error_in = 0.001;
% xin_new = x_veh;
% yin_new = y_veh;
for i = 1:length(x_veh)
      xin_new = x_veh(i);
      yin_new = y_veh(i);
      error_in = 0.001;
          while error_in>=0
          xin_new = xin_new + 0.01;
          yin_new = 1*sin(2*pi*xin_new/25);
          slope_in = (yin_new-y_veh)/(xin_new-x_veh);
          slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
          error_in = slope_curve_in-slope_in;
          xin_new = xin_new+0.01;
          end
          x_save(:,i) = xin_new;
          y_save(:,i) = yin_new;
         error = error_in; this is line 29
end
xfar_in = xin_new;
yfar_in = yin_new;

I change the code accordingly still I have the following errors.

Size mismatch (size [1 x 1] ~= size [2 x 2]).
The size to the left is the size of the left-hand side of the assignment.
Function 'MATLAB Function1' (#47.762.770), line 29, column 9:
"error_in"
Launch diagnostic report.
Component:MATLAB Function | Category:Coder error
Errors occurred during parsing of MATLAB function 'cvm/MATLAB Function1'
Component:MATLAB Function | Category:Coder error
Simulink cannot determine sizes and/or types of the outputs for block 'cvm/MATLAB Function1' due to errors in the block body, or limitations of the underlying analysis. The errors might be inaccurate. Fix the indicated errors, or explicitly specify sizes and/or types for all block outputs.
Component:MATLAB Function | Category:Coder error
Simulink cannot determine sizes and/or types of the outputs for block 'cvm/MATLAB Function1' due to errors in the block body, or limitations of the underlying analysis. The errors might be inaccurate. Fix the indicated errors, or explicitly specify sizes and/or types for all block outputs.
Component:Simulink | Category:Model error
An error occurred while propagating data type 'double' through 'cvm/MATLAB Function1'.
Component:Simulink | Category:Model error

Sanjal C C 2018-6-30

编辑：Walter Roberson 2018-6-30

在 MATLAB Online 中打开

function [xfar_in,yfar_in] = fartheta(y_veh,x_veh,error_in)
% c=0.0100;
% error_in=0;
% amplitude=1;
% xfar_in=zeros(2,1);
% yfar_in=zeros(2,1);
% xin_new=zeros(2,1);
% yin_new=zeros(2,1);
% slope_in=zeros(2,1);
% slope_curve_in=zeros(2,1);
x_save = zeros(2,1);
y_save = zeros(2,1);
% coder.varsize('x_save',[1, 2 * length(x_veh)]);
% coder.varsize('y_save',[1, 2 * length(y_veh)]);
% error_in = 0.001;
% xin_new = x_veh;
% yin_new = y_veh;
for i = 1:length(x_veh)
      xin_new = x_veh(i);
      yin_new = y_veh(i);
      error_in = 0.001;
          while all(error_in(:)>=0)
          xin_new = xin_new + 0.01;
          yin_new = 1*sin(2*pi*xin_new/25);
          slope_in = (yin_new-y_veh)/(xin_new-x_veh);
          slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
          error_in = slope_curve_in-slope_in;
          xin_new = xin_new+0.01;
          end
%        error = error_in;
end
        x_save(:,i) = xin_new;
        y_save(:,i) = yin_new;
        error_in=0.001*ones(length(y_veh),length(x_veh));
% xfar_in = xin_new;
% yfar_in = yin_new;
% yfar_in = y_save
% xfar_in = xin_new;
% yfar_in = yin_new;
% d_in = sqrt(((x_veh-xfar_in)^2) + ((y_veh-yfar_in)^2));
%  
% m1=tan(hdg);
% m2=(y_veh-yfar_in)/(x_veh-xfar_in);
% farangle=atan((m1-m2)/(1+m1*m2));

Please let me know were I have gone?

Sanjal C C 2018-6-30

Yeah really sorry.I could not see your comments and I have attached previously my updated code.

Walter Roberson 2018-6-30

在 MATLAB Online 中打开

Maybe you want something like,

function [xfar_in,yfar_in] = fartheta(y_veh,x_veh,error_in)
    nveh = length(x_veh);
    x_save = zeros(1, nveh);
    y_save = zeros(1, nveh);
    for i = 1:nveh
      xin_new = x_veh(i);
      yin_new = y_veh(i);
      error_in = 0.001;
      while true
        xin_new = xin_new + 0.01;
        yin_new = 1*sin(2*pi*xin_new/25);
        slope_in = (yin_new-y_veh(i)) ./ (xin_new-x_veh(i));
        slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
        error_in = slope_curve_in-slope_in;
        if error_in <= 0
          break;
        end
        xin_new = xin_new+0.01;
      end
      x_save(1,i) = xin_new;
      y_save(1,i) = yin_new;
    end
    and here calculate xfar_in and yfar_in