Hi!.Can anyone please help me how to get rid of this errors.I herby attach my code and the errors.

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Sanjal C C
Sanjal C C 2018-6-29
评论： Joe Jones 2022-7-12
function [xfar_in,yfar_in] = fartheta(y_veh, x_veh)
% c=0.0100;
% error_in=0;
% amplitude=1;
% xfar_in=zeros(2,1);
% yfar_in=zeros(2,1);
% xin_new=zeros(2,1);
% yin_new=zeros(2,1);
% slope_in=zeros(2,1);
% slope_curve_in=zeros(2,1);
x_save = zeros(2,1);
y_save = zeros(2,1);
% coder.varsize('x_save',[1, 2 * length(x_veh)]);
% coder.varsize('y_save',[1, 2 * length(y_veh)]);
% error_in = 0.001;
% xin_new = x_veh;
% yin_new = y_veh;
for i = 1:length(x_veh)
xin_new = x_veh(i);
yin_new = y_veh(i);
error_in = 0.001;
while error_in>=0
xin_new = xin_new + 0.01;
yin_new = 1*sin(2*pi*xin_new/25);
slope_in = (yin_new-y_veh)/(xin_new-x_veh);
slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
error_in = slope_curve_in-slope_in;
xin_new = xin_new+0.01;
end
x_save = [x_save;xin_new];
y_save = [y_save;yin_new];
end
xfar_in = x_save;
yfar_in = y_save;
% xfar_in = xin_new;
% yfar_in = yin_new;
% d_in = sqrt(((x_veh-xfar_in)^2) + ((y_veh-yfar_in)^2));
%
% m1=tan(hdg);
% m2=(y_veh-yfar_in)/(x_veh-xfar_in);
% farangle=atan((m1-m2)/(1+m1*m2));
  1 个评论
Joe Jones
Joe Jones 2022-7-12
Dear
Did you solve this problem ?
I also had this problem recently. "An error occurred while propagating data type 'double' through 'adrc/cg_adrc'". (the last problem in the attached picture 'erroes.JPG')
Hope you can help me if possible. Thank you.

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回答（1 个）

Walter Roberson
Walter Roberson 2018-6-30
You need to preallocate the output variable and assign into the appropriate locations in it, instead of dynamically growing your array.
  10 个评论
显示 8更早的评论
Walter Roberson
Walter Roberson 2018-6-30
Maybe you want something like,
function [xfar_in,yfar_in] = fartheta(y_veh,x_veh,error_in)
nveh = length(x_veh);
x_save = zeros(1, nveh);
y_save = zeros(1, nveh);
for i = 1:nveh
xin_new = x_veh(i);
yin_new = y_veh(i);
error_in = 0.001;
while true
xin_new = xin_new + 0.01;
yin_new = 1*sin(2*pi*xin_new/25);
slope_in = (yin_new-y_veh(i)) ./ (xin_new-x_veh(i));
slope_curve_in = (1*2*pi/25)*cos(2*pi*xin_new/25);
error_in = slope_curve_in-slope_in;
if error_in <= 0
break;
end
xin_new = xin_new+0.01;
end
x_save(1,i) = xin_new;
y_save(1,i) = yin_new;
end
and here calculate xfar_in and yfar_in

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