How can I find the time difference between each consecutive rows?

12 次查看(过去 30 天)
I have a column in which date and time is mentioned, I want to find the time difference between every consective rows . Also how can I find the time difference in seconds , minutes, hours , days , weeks , months and years.
TimeStamp ; TimeDiff;
2014-09-02 07:48:09.567; NULL;
2014-09-02 07:51:02.810 ; 00:03:00
2014-09-02 08:06:13.387 ; 00:15:00
2014-09-02 08:37:09.647; 00:31:00
2014-09-02 14:32:00.113 ; 05:55:00
2014-09-02 16:16:42.593; 01:44:00

采纳的回答

Stephen23
Stephen23 2018-7-3
编辑:Stephen23 2018-7-3
Convert to datetime. The use caldiff (or diff).
  8 个评论
Ammy
Ammy 2018-7-3
Thank you very much. But please If I want the time difference interval in only seconds or minutes then is there any way ?
Stephen23
Stephen23 2018-7-3
编辑:Stephen23 2018-7-3
@Noor Bano: yes, you can easily calculate this yourself. Serial date numbers (e.g. the output from datenum) are given in days, so...
  • Multiply the days by 24 to get hours (there are 24 hours in 1 day).
  • Multiply again by 60 to get minutes (there are 60 minutes in 1 hour).
  • Multiply again by 60 to get seconds (there are 60 seconds in 1 minute).
For example, to get the differences in minutes:
>> C = {'2014-09-02 07:48:09.567';'2014-09-02 07:51:02.810';'2014-09-02 08:06:13.387';'2014-09-02 08:37:09.647';'2014-09-02 14:32:00.113';'2014-09-02 16:16:42.593'};
>> N = datenum(C,'yyyy-mm-dd HH:MM:SS.FFF');
>> D = diff(N);
>> D*24*60
ans =
2.8874
15.1763
30.9377
354.8411
104.7080

请先登录,再进行评论。

更多回答(1 个)

M.Devaki Mohanarangam
Time = [16/04/2023 14:44:22
16/04/2023 14:44:26
16/04/2023 14:44:31
16/04/2023 14:44:36
16/04/2023 14:44:42
16/04/2023 14:44:46
16/04/2023 14:44:51
16/04/2023 14:44:56
16/04/2023 14:45:02
16/04/2023 14:45:06 ]
how to find time difference in loop condtion? plz help

类别

Help CenterFile Exchange 中查找有关 Dates and Time 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by