Why changes my string into a double in a for loop
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Hello!
When I want to change a cell in a matrix with the original value NULL into 'C', the 'C' turns into the value 67. This is my code:
for j=1:99
percentage2 = j/99
mDataTest(m,1) = str2double(data{1}{j});
mDataTest(m,2) = 0;
for i = 3:50
percentage1 = j/50
if(strcmp(data{i}{j},''))
mDataTest(m,i) = 'C';
elseif(strcmp(data{i}{j},'NULL'))
mDataTest(m,i) = 'C' ;
else
mDataTest(m,i) = str2double(data{i}{j}); %make matrix with data
end
end
m=m+1;
n=3;
end
Where data is a matrix filled with strings and numeric values. The goal of this is to change all values that are '' or 'NULL' into a string. Eventually I want to replace all 'C' with the median of that vector. Can someone help me?
采纳的回答
If you don't want mDataTest to be double, then don't use str2double when you create it.
4 个评论
Rosalie van der Weide
2018-7-3
Walter Roberson
2018-7-3
It is not possible to assign both numeric and characters to the same array except by using cell array.
This might be what you want. As Walter says, mDataTest must be kept as type cell array.
for j=1:99
percentage2 = j/99
mDataTest{m,2} = 0;
for i = 3:50
percentage1 = j/50
if(strcmp(data{i}{j},'') || strcmp(data{i}{j},'NULL'))
mDataTest{m,i} = 'C';
else
mDataTest{m,i} = str2double(data{i}{j});
end
end
m=m+1;
n=3;
end
Rosalie van der Weide
2018-7-3
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