Coping cell array but skipping a specific column

Question

ErikaZ 2018-7-4

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/408658-coping-cell-array-but-skipping-a-specific-column

回答： ErikaZ 2018-7-5

I have:

EMG =
    1×3 cell array
      {3×16 cell}    {3×15 cell}    {3×15 cell}

I need to copy the "first" 10 columns of each cell but for each iteration I need to skip column 1, for the second iteration column 2, for the third iteration column 3, and so on. The resulting cell array (3x30) needs to be:

Skipping first column                
column1,        column2,        column3,        column4,       column5,        column6…       column28,     column29,           column30
column2ofcell1, column2ofcell2, column2ofcell3, column3ofcell1,column3ofcell2, column3ofcell3…column11ofcell1, column11ofcell2, column11ofcell3
                
Skipping second column                
column1,        column2,        column3,        column4,        column5,        column6…       column28,    column29,            column30
column1ofcell1, column1ofcell2, column1ofcell3, column3ofcell1, column3ofcell2, column3ofcell3…column11ofcell1, column11ofcell2, column11ofcell3

where the column of each cell is copied.

I put the word first in quotations because the columns to be extracted are not contiguous, so it is not always 1:10, the fist iteration is 2:11 because I need to skip #1, on the second iteration I need to skip #2 so I need to copy, 1&3:11, for the third iteration I need to skip #3 and copy 1:2&4:11 and so on until I skip the first 10 columns.

Thank you,

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

ErikaZ 2018-7-5

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/408658-coping-cell-array-but-skipping-a-specific-column#answer_327685

在 MATLAB Online 中打开

Not the best code but it works

for cv=1:10
    %Create cell array with train data
    EMG_InputSeries = []; Angle_TargetSeries = []; Angle_Moment_TargetSeries = [];
    EMG_InputSeries=cellfun(@(x) x(:,1:11),EMG,'uni', false);
    Angle_TargetSeries=cellfun(@(x) x(:,1:11),Angle,'uni', false);
    Angle_Moment_TargetSeries=cellfun(@(x) x(:,1:11),Angle_Moment,'uni', false);
      %Delete Test column
      for i=1:numel(EMG_InputSeries)
          EMG_InputSeries{i}(:,cv)=[];
          Angle_TargetSeries{i}(:,cv)=[];
          Angle_Moment_TargetSeries{i}(:,cv)=[];
      end
      %Organize as walk,up,down,walk,up,down
      EMG_InputSeries= reshape(vertcat(EMG_InputSeries{:}), [3 30]);
      Angle_TargetSeries= reshape(vertcat(Angle_TargetSeries{:}), [1 30]);
      Angle_Moment_TargetSeries= reshape(vertcat(Angle_Moment_TargetSeries{:}), [1 30]);
  end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

Image Analyst 2018-7-4

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/408658-coping-cell-array-but-skipping-a-specific-column#answer_327378

在 MATLAB Online 中打开

Each of your cells in your cell array contains another cell array. We don't know what that cell array's cells contain but it doesn't matter. To extract/crop out the first 10 columns of the contained cell array, simply do

for k = 1 : length(ca)
  thisCellsContents = ca{k};  % This is another cell array
  % Take the first 10 columns of the cell array called "thisCellsContents"
  ca{k} = thisCellsContents(:, 1:10);
end

Now I have no idea what you mean by iterations. Do you want to put that "crop first 10 columns" code into a for loop where you iterate it for some reason?

2 个评论
显示无隐藏无

ErikaZ 2018-7-5

I put the word first in quotations because the columns to be extracted are not contiguous, so it is not always 1:10, the fist iteration is 2:11 because I need to skip #1, on the second iteration I need to skip #2 so I need to copy, 1&3:11, for the third iteration I need to skip #3 and copy 1:2&4:11 and so on until I skip the first 10 columns.