vpasolve and for loop

2 次查看(过去 30 天)
I G
I G 2018-7-6
I am trying to solve numerically symbolic equation. But one variable in my equation is series of values
zv=1:-0.1:0
So, according to my code:
zv=1:-0.1:0
n=length(zv);
j=1:n;
C=15;
eqn=C-64.*(1-zv(j))==0;
R=vpasolve(eqn,x(j),1)
I got mistake in the last row that
`Index exceeds matrix dimensions`.
Other solution which is working is with for loop, but I dont know how to put all solutions (R) in one variable. I got list in my working space where values are changing and it stops when I use all
`zv`
terms:
syms x;
for zv=1:-0.1:0
C=15;
eqn=C-64.*(1-zv(j))==0;
R=vpasolve(eqn,x,1)
end

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Number Theory 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by