Error finding and graphing max values of data (Error using horzcat Dimensions of matrices being concatenated are not consistent. )

2 次查看（过去 30 天）
Zaman Chini
Zaman Chini 2018-7-6
评论： Zaman Chini 2018-7-9
I'm trying to graph multiple sets of .csv data and display the max value for each data set on the graph itself. This has worked for all of my data sets except for one, which I keep getting the error "Error using horzcat Dimensions of matrices being concatenated are not consistent. The following is the code I've been using for two data sets, which I have attached to the post. TEK00055 is the one with errors and TEK00057 is the one without issues.
figure;
tmd=load('TEK00055.CSV');
x=5.+tmd(:,1);
y=5.*tmd(:,2);
plot(x,y)
xlabel('Time (s)')
ylabel('disp (mm)')
indexmax = find(max(y) == y);
xmax = x(indexmax);
ymax = y(indexmax);
strmax = ['Maximum = ',num2str(ymax)];
text(xmax,ymax,strmax,'HorizontalAlignment','right');
figure;
tmd=load('TEK00057.CSV');
x=5.+tmd(:,1);
y=5.*tmd(:,2);
plot(x,y)
xlabel('Time (s)')
ylabel('disp (mm)')
indexmax = find(max(y) == y);
xmax = x(indexmax);
ymax = y(indexmax);
strmax = ['Maximum = ',num2str(ymax)];
text(xmax,ymax,strmax,'HorizontalAlignment','right');
For the TEK00057 data, a graph comes out exactly how I want, with the maximum y-value being labelled, but the TEK00055 data is giving me errors. From looking through the excel files, i can't find any major differences between the two. Any help would be appreciated.
  6 个评论
显示 4更早的评论
Geoff Hayes
Geoff Hayes 2018-7-9
Zaman - but what are the dimensions of ymax? Perhaps there are two or more idenitcal maximum values. And so the horizontal concatenation will fail when trying to create this string. If you are unsure, then put in some code like
strmax = ['Maximum = ',num2str(ymax(1))];
so that you always grab the first element of ymax.
Zaman Chini
Zaman Chini 2018-7-9
You were correct. I had to designate xmax=xmax(1) and ymax=ymax(1), so that there would only be one of each values in the text line. Someone posted an answer, and I gave that credit, but thank you for helping me with my issue.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Unai San Miguel
Unai San Miguel 2018-7-9
Your TEK00055.csv data has three data points with maximum y-values:
>> xmax
xmax =
6.8720
6.8730
6.9890
>> ymax
ymax =
0.2380
0.2380
0.2380
And then
>> num2str(ymax)
ans =
3×5 char array
'0.238'
'0.238'
'0.238'
is a 3x1 array, which cannot be horizontally concatenated with a single string 'Maximum = '.
You can use ['Maximum = ', str2num(ymax(1))] to display the first maximum occurrence, or any other solution.
  1 个评论
Zaman Chini
Zaman Chini 2018-7-9
What you and Geoff Hayes said about designating ymax(1) cause I had multiple values in ymax that were the same was correct. What I ended up doing to get a reasonable result is
figure;
tmd=load('TEK00055.CSV');
x=5.+tmd(:,1);
y=5.*tmd(:,2);
plot(x,y)
% xlim([0,10])
xlabel('Time (s)')
ylabel('disp (mm)')
indexmax = find(max(y) == y);
xmax = x(indexmax);
ymax = y(indexmax);
xmax = xmax(1);
ymax = ymax(1);
strmax = ['Maximum = ',num2str(ymax)];
text(xmax,ymax,strmax,'HorizontalAlignment','right');
I had to designate the xmax=xmax(1) and ymax=ymax(1), so that there was only one of each value to be noted in the text line.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by