Convert duration from MM:SS to M:SS.

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Gianluca Finotti
Gianluca Finotti 2018-7-12
评论： Gianluca Finotti 2018-7-13
Hello everyone, I have a duration vector like this:
00:00
00:01
00:01
00:02
00:02
00:03
00:03
00:03
00:05
It only goes from 0 to 4 minutes so, in the plots I don't want to show something like: 01:05, but rather 1:05. That is, I want to get rid of the first digit and convert from mm:ss to m:ss. Is this possible?
Thank you for your time, Gianluca

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回答（1 个）

Florian Floh
Florian Floh 2018-7-13
Hello!
In order to achieve the desired time-format (or date format) you have to take a closer look at the function "datetime".
I tried the following code by myself and it should give the result you wish to achieve:
%Code
% Set up the vector (just for me to test) containing the time 'mm:ss'
a= ["01:00";
"01:01";
"01:01";
"01:02";
"01:02";
"01:03";
"01:03";
"01:03";
"01:05"];
% get the size of a
[rowsA colsA] = size(a);
% loop through the array in order to change the time-format
for i=1: rowsA
a(i)= datetime(a(i), 'InputFormat', 'mm:ss', 'Format', 'm:ss');
end
I hope this answer was helpful.
Kind regards, Florian
  1 个评论
Gianluca Finotti
Gianluca Finotti 2018-7-13
I forgot to mention that the class of the variable is "duration", so that code does not really work in this case. But I think I have found the solution: |
a.Format = 'm'
I still don't know whether I like it because in this case I get:
0 min
0.016667 min
0.016667 min
0.033333 min
0.033333 min
0.05 min
I think I'd rather have just the number without the "min". I don't know whether that is going to create problems with the plots. But we'll see.
Anyways, thank you very much for your answer.

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