inputParser with only a value, not a name-value pair
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Is it possible to use inputParser with only a value, not a name-value pair. So that when you send a function a specific argument, the argument is automatically set to a variable, without a variable name needed to be given in the function call?
Instead of
a = findArea(13,'shape','square');
You could just send findArea 'square', like:
a = findArea(13,'square');
And within the function, it would recognize that square can only be a shape and set shape's value to 'square'.
回答（1 个）
Fangjun Jiang
2018-7-13
0 个投票
Yes. You would make that a required argument, not an optional argument.
function a = findArea(width,Shape,varargin)
....
addRequired(p,'shape',defaultShape,... @(x) any(validatestring(x,expectedShapes)));
2 个评论
Gregory Dachner
2018-7-17
Fangjun Jiang
2018-7-18
should be
addRequired(p,'shape', @(x) any(validatestring(x,expectedShapes)));
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2018-7-13
2018-7-18
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