inputParser with only a value, not a name-value pair

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Gregory Dachner
Gregory Dachner 2018-7-13
评论： Fangjun Jiang 2018-7-18
Is it possible to use inputParser with only a value, not a name-value pair. So that when you send a function a specific argument, the argument is automatically set to a variable, without a variable name needed to be given in the function call?
As an example, taken from https://www.mathworks.com/help/matlab/ref/inputparser.html :
Instead of
a = findArea(13,'shape','square');
You could just send findArea 'square', like:
a = findArea(13,'square');
And within the function, it would recognize that square can only be a shape and set shape's value to 'square'.

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回答（1 个）

Fangjun Jiang
Fangjun Jiang 2018-7-13
Yes. You would make that a required argument, not an optional argument.
function a = findArea(width,Shape,varargin)
....
addRequired(p,'shape',defaultShape,... @(x) any(validatestring(x,expectedShapes)));
  2 个评论
Gregory Dachner
Gregory Dachner 2018-7-17
I'm not sure what you expect this to do, but it breaks the function, causes all inputs to return the error:
Error using inputParser/addRequired Too many input arguments.
Fangjun Jiang
Fangjun Jiang 2018-7-18
should be
addRequired(p,'shape', @(x) any(validatestring(x,expectedShapes)));

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