How do I find no. of instances of each value till it changes?

1 次查看（过去 30 天）
Advay Pawar
Advay Pawar 2018-7-18
评论： Rik 2018-7-18
I have the following input: [4 4 4 4 4 4 0 0 0 4 4 4 4 4 4 0 0 0 0 0 0 0 0 4 4 4 4 4];
I want MATLAB to give me the number of 4s and 0s in each set till the digit changes. So I want my output to be: [6 3 6 8 5].
Thank you!

请先登录，再回答此问题。

回答（2 个）

Rik
Rik 2018-7-18
编辑：Rik 2018-7-18
You can use the runlength function that Jan made.
Another option is using the code below.
input = [4 4 4 4 4 4 0 0 0 4 4 4 4 4 4 0 0 0 0 0 0 0 0 4 4 4 4 4];
diff([0 find(diff(input)) numel(input)])
Paolo
Paolo 2018-7-18
编辑：Paolo 2018-7-18
This can be achieved nicely with regular expressions. Capture a digit and backreference back to the same digits to find the patterns of consecutive numbers.
input = [4 4 4 4 4 4 0 0 0 4 4 4 4 4 4 0 0 0 0 0 0 0 0 4 4 4 4 4];
num = regexp(char(input+'0'),'(\d)\1+','match');
n = cellfun(@numel, num)
>>n
6 3 6 8 5
  6 个评论
显示 4更早的评论
Paolo
Paolo 2018-7-18
Cheers! Your solution is indeed very efficient. Reason as to why I asked you to do it is because I am on mobile and do not have pc access.
Rik
Rik 2018-7-18
It's a not-uncommon question, so I've seen some solutions before. My first instinct with the first I saw was a for-loop, so yours is miles better already.
And yeah, it's a bit much to copy this code to Matlab online or the app, just to have a benchmark, so I fully understand ;)

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by