Why does there is no numerical solution but a structure.

2018 7 18
1 个回答
回答已采纳
更新时间：2018 8 2
1 次查看（30 天）

0 个投票

syms vc(t) vin Rc Cc Vc1 Lk Lin ip(t) il(t) ic(t)
eq1=((-1)*vin+Lin*diff(il, t)+ vc == 0);
eq2= (vc-Lk*diff(ip , t) == 0);
eq3= (Cc*diff(vc, t)+(1/Rc)*(vc-vin)- il+ip == 0);
cond=[vc(0)==Vc1];
svc=dsolve(eq1,eq2,eq3,cond)

请先登录，再回答此问题。

 采纳的回答

madhan ravi
madhan ravi 2018-7-18
编辑：madhan ravi 2018-8-2

1 个投票

Hi,
It’s because the solution is too long plus the solution output is one that’s why and all the variables are symbolic.
if you want to view the solution type
svc.ip
svc.il
svc.vc
if you want to view the solution without structure then use the following code which has three outputs:
[ip,il ,vc ]=dsolve(eq1,eq2,eq3,cond)

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Mathematics 的更多信息

产品

版本

R2015a

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by