WHY EVERY TIME I AM GETTING THE ERROR "Cell contents assignment to a non-cell array object." I need to store the value of "ISG" which is a one dimensional array(array elements changes for every i,j) into every cell of "VarIsg" .. PLEASE HELP ME OUT

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RAJ DATTA
RAJ DATTA 2018-7-20
回答： RAJ DATTA 2018-7-29
for i=1:3
for j=1:3
mat_cor= InsideSquareCoordinate2{i,j};
mat_data=InsideSquareGrade2{i,j};
mat_data=mat_data(mat_data~=0);
mat_dl=length(mat_data);
%%%%%%%%%%%****-----------------------------------------------------------------------------------------****%
% mat_data(:,n1)
% n1=1;
% if ~isempty (InsideSquareCoordinate2{i,j})
VarIsg=0;
tempPointCord=InsideSquareCoordinate2{i,j};
xCordInside=tempPointCord(:,1);
yCordInside=tempPointCord(:,2);
for i1=1:mat_dl
for j1=1:mat_dl
if (i1~=j1)
d=sqrt((xCordInside(i1)-xCordInside(j1))^2 + (yCordInside(i1)-yCordInside(j1))^2);
if((xCordInside(j1)-yCordInside(i1))==0)
theta=90;
else
theta=180.*atan((yCordInside(j1)-yCordInside(i1))./(xCordInside(j1)-yCordInside(i1)))./pi;
end
minlag=10; nlag=3; laginv=10; clear('ISG')
for k=1:nlag
llag(k)=minlag+(k-1)*laginv;
hlag(k)=llag(k)+laginv;
b=abs(d.*sin(theta-azm));
if((llag(k)<=d && d<hlag(k))&&(lowangle<=theta &&theta<upangle)&&(b<=maxbandw))
ISG(k)= sum((mat_data(i1)- mat_data(j1)).^2)/(2*mat_dl);
end
end
ISG
VarIsg{i,j}=ISG
end
end
end
% ISG
% VarIsg{i,j}=0;
end
end

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采纳的回答

Walter Roberson
Walter Roberson 2018-7-20
You have
VarIsg=0;
so VarIsg is numeric.
Later you do
VarIsg{i,j}=ISG
which attempts to access VarIsg as if it is a cell array. But it is not a cell array, it is numeric.
Your line
VarIsg=0;
should probably be
VarIsg{i,j} = 0;

更多回答（1 个）

RAJ DATTA
RAJ DATTA 2018-7-29
thank u all for your valuable replies...it works..

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