getting an image matrix when I have the image.
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My code to produce a white F on a black background:
f_shape = [0,0;1,0;1,2;2,2;2,3;1,3;1,5;3,5;3,6;0,6;0,0]*[1,0;0,-1];
r = ceil(max(range(f_shape))*sqrt(2));
kappa =2;
R = ceil(kappa*r);
f_img = zeros(2*R);
f_shape = f_shape + R*[1,1];
imshow(f_img);
hold;
fill(f_shape(:,1),f_shape(:,2),'w');
daspect = [1,1,1];
Now I want to apply imrotate to this 36 times 36 image matrix. The only way I can think of is to save it as a png, and then imread it. Do I really have to do that? Sound slow, and wrong in principle. It is also likely to result in lots of pointless files littering my hard disk.
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Image Analyst
2018-7-20
Simply call imrotate() on f_img. Why do you think you can't do that???
rotatedImage = imrotate(f_img, angle);
4 个评论
Image Analyst
2018-7-21
You need to understand the concept of an actual digital image, which has pixel values, and the concept of a graphical overlay, where you put computer graphics in over the image. The Image Processing Toolbox commands, starting with im or bw, work on the image itself, not with anything you may have put on top of them in the overlay.
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