counting the correct interval and stop at the end of it

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Gali Musa
Gali Musa 2018-7-21
编辑： KALYAN ACHARJYA 2018-7-30
Pd = 480; inter = 18; Cap = 200; hrs = 8640; initial = Cap; yyyy(1) = initial; yyy(1) = 0;
for e_ref = Pd:Pd:hrs for t=1:inter
if Pd(Pd >= 72 & Pd < 120)
yyy(t+1) = ((-0.00005667*e_ref(t) + 100)/100);
yyyy(t+1) = yyy(t+1)*Cap;
e_ref(t+1) = e_ref(t) + Pd;
elseif Pd == 480
yyy(t+1) = ((-0.00008999*e_ref(t) + 100)/100);
yyyy(t+1) = yyy(t+1)*Cap;
e_ref(t+1) = e_ref(t) + Pd;
end
end
end

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回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2018-7-21
%insert the following code within for loop, when Pd becomes 480, the loop execution stop
if Pd==480
return;
end
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