How can I solve single nonlinear equation

196 次查看(过去 30 天)
How can I solve the following equation using Matlab, 6.84e24X^1.8164+9.95E13*X+1=0, Could you please help with syntax?

采纳的回答

Aarti Dwivedi
Aarti Dwivedi 2018-7-23
func = @(x) coeff1*x.^exp1 + coeff2*x.exp2 + b;
x0 = 1; % starting point
roots = fzero(func,x0)
In the above code snippet, you can define your function, choose a starting point and fzero will give you the roots. It is generally a good idea to plot your function to get an idea of what it looks like. You can do that in the following manner:
x_interval = -10:10
fplot(func,x_interval)
  3 个评论
Walter Roberson
Walter Roberson 2018-7-23
There is no real-valued solution for
6.84e24X^1.8164+9.95E13*X+1=0
Consider that if X is positive then all of the terms are positive and so the equation cannot be equal to 0. But if X is negative and real-valued, then you have a negative number raised to a fractional power, which is something that is defined as returning a complex result.
Anwar
Anwar 2018-7-23
Many thanks, Roberson, for highlighting that, I missed that and was trying to solve in different ways.
Thank you once again.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Mathematics 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by