Comparing elements between a character and a numerical column
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Not sure if this is written correctly. Suppose there is a cell array where the first column holds characters ie) 'con', 'func', key', and the second column holds numerical values ie) 74 85 98. For x = 1:length(Event) [where event is the array], if event{x,1} is 'con' AND the cell immediately after it (x+1) is 'key', take the horizontal values and place those in a new array. For example:
Column 1 = ['con', 'key', 'con', 'con', 'var', 'con', key'] Column 2 = [ 74 85 94 67 56 84 23]
The new array would look like Column 1 = ['con', 'key', 'con, 'key'] column 2 = [74 85 84 23]
for x = 1:length(event)
if event{x,1} == 'con' & event{x+1,1} == 'key'
iEvent = event{x,:}
end
end
One of the issues I think is that == does not work with characters?
采纳的回答
Here ares some fake data using your pattern and a solution. The solution identifies the rows of 'data' where 'key' follows 'con' and puts all of those rows into a new variable, 'output'.
data = {
'con' 74;
'key' 85;
'con' 94;
'con' 67;
'var' 56;
'con' 84;
'key' 23
'con' 67;
'var' 56;
'con' 84;
'key' 23};
% row indices of con & key
isCon = strcmp(data(:,1), 'con');
isKey = strcmp(data(:,1), 'key');
% rows of 'key' where 'con' preceded
ConKeyIdx = find(isKey(2:end) & isCon(1:end-1));
ConKeySubs = sort([ConKeyIdx;ConKeyIdx+1]); %row numbers of con-key neighbors
output = data(ConKeySubs,:);
output =
{'con'} {[74]}
{'key'} {[85]}
{'con'} {[84]}
{'key'} {[23]}
{'con'} {[84]}
{'key'} {[23]}
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