- Do some pre-analysis and find a subspace of values for the parameters theta that implies these bounds on z.
- Choose f() to be of a form that is innately and globally bounded, e.g., z=arctan(g(x,y;theta))/pi + 0.5. This is the most common approach when f(x,y,theta) must satisfy bounds over a continuum of x and y.
- Use fmincon() or ga() instead of fit(). You can define any constraints you want in those solvers, in particular 0<=f(x,y; theta)<=1. The problem is that this constraint will often correspond to disjoint, non-connected regions in the feasible parameter space theta. It can be hard for the solvers to find global minima over non-connected feasible sets.
Fitting and imposing certain range in variables
10 次查看(过去 30 天)
显示 更早的评论
I am trying to fit surface data z=f(x,y) to a function with several parameters using the "fit" function of Matlab.
The resulting function must accomplish that 0<z<1 for the range 0<x<1 at any y. Is it possible to apply it? I have only seen the possibility to impose a range for the parameters, but not the variables.
Thank you!
0 个评论
采纳的回答
Matt J
2018-7-24
编辑:Matt J
2018-7-24
No, it is not possible to apply that requirement directly through the fit() function. There are perhaps 3 possible approaches you can take,
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Quadratic Programming and Cone Programming 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!