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How do I count the number of new occurrences of a number in an array?

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I have an array given as
x = [1 1 1 1 1 1 1 2 2 1 1 1 3 3 3 3 1 1 1 1 3 1 5]
I am trying to calculate how many new occurrences there are of the number 1. Importantly, this should ignore whether or how many times 1 recurs in the adjacent cell. In the above example, the answer would be 4, because there are 4 instances of 1 appearing, even though they differ in length.
Thanks!

回答(1 个)

Paolo
Paolo 2018-7-24
nnz(diff([0 (x==1)])==1)

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