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How can I create a matrix of linestyles for plot to loop through?

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Connor Sherod
Connor Sherod 2018-7-25
评论： Connor Sherod 2018-7-26
So, I have this:
linedex={'-','--','-.',':'};
x=[-2;-3;-4];
for i=1:4
mmm= [0.0803 0.1912 0.1245
0.0239 0.3246 0.1581
0.0164 0.5584 0.2294]; %%%For each loop it gets a different set of values, this is and example one, with the columns being min,max,mean
hold on
plt=plot(x,mmm)
plt.LineStyle(i)=linedex(i);
end
I've also tried plotting them individually, where its the same linedex and loop replacing mmm with three vectors instead.
x=[-2 -3 -4]
min=[0.0803 0.0239 0.0164]
max=[0.1912 0.3246 0.5584]
mean=[0.1245 0.1581 0.2294]
plot(x,min,x,max,x,mean)
but then how would I call to those specific lines, to have them all be one style, while the next set of min,max, and mean are in a new style/and then colors eventually?

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采纳的回答

Stephen23
Stephen23 2018-7-26
编辑：Stephen23 2018-7-26
You were almost there, you just need to use the right kind of cell array indexing:
C = {'-','--','-.',':'};
x = [-2;-3;-4];
for k = 1:numel(C)
% Simpler:
mmm = k+[0.0803,0.1912,0.1245;0.0239,0.3246,0.1581;0.0164,0.5584,0.2294];
plot(x,mmm,C{k})
% OR alternatively
%plt = plot(x,mmm);
%plt.LineStyle = C{k};
hold on
end
Which produces this:

更多回答（1 个）

Sushant Mahajan
Sushant Mahajan 2018-7-25
编辑：Sushant Mahajan 2018-7-25
You can use a combination of eval and sprintf. Here I am plotting successive powers of sin(x).
linestyles={'-','--','.-'};
x=linspace(0,90,100);
for i=1:3
eval(sprintf('plot(x,sind(x).^%d,''%s'')',i,cell2mat(linestyles(i))))
hold on
end
Hope this helps!
  2 个评论
Stephen23
Stephen23 2018-7-26
编辑：Stephen23 2018-7-26
Why on earth do you use eval for this? This is bad advice: eval is totally unnecessary, and pointlessly teaches bad habits to other beginners: using eval for trivial code like this is how beginners force themselves into writing slow, complex, buggy code that is hard to debug. Avoid using this code. Read this to know why:
https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval
The code is simpler, neater, and more efficient without eval:
C = {'-','--','.-'};
x = 0:90;
for k = 1:numel(C)
plot(x,sind(x).^k,C{k})
hold on
end

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