Write a function count_odd that takes two arguments: low_bound and high_bound. The function counts how many odd values are there between the low_bound and the high_bound. Last it returns the number of odd numbers between these two values.
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Here is what I have. All help is appreciated.
function count_odd(low_bound, high_bound)
% promt user to enter low_bound and high_bound
low_bound=input('Enter low bound: ')
high_bound=input('Enter high bound: ')
end
3 个评论
Adam
2018-7-26
You are passing low_bound and high_bound into the function so you shouldn't then be asking for them as input.
Since it is your question though you need to show a little more effort that that on the actual question at hand - i.e. counting odd values.
doc rem
doc sum
would both be helpful for doing that.
Layken McMeekin
2018-7-26
Adam
2018-7-26
The questions asks you to return it, not display it, so just calculate it in a variable and return that variable from the function.
采纳的回答
madhan ravi
2018-7-26
编辑：madhan ravi
2018-7-26
l=1 %lower bound
u = 9 %upper bound
boundary_vector=l:u
counter = 0;
for i = 1:length(boundary_vector)
if rem(boundary_vector(i),2)==0
counter = counter + 1;
end
end
odds = length(boundary_vector) - counter
4 个评论
Layken McMeekin
2018-7-26
Adam
2018-7-26
That's what often happens when you just copy someone's answer rather than work out how to do it yourself!
Layken McMeekin
2018-7-26
madhan ravi
2018-7-26
编辑：madhan ravi
2018-7-26
Updated the code, you can try it now
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