plot two equation by matlab

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khouloud abiedh 2018-7-27

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评论： khouloud abiedh 2018-7-30

hello everyone i need to plot a non linear equation by matlab who can help me in code please .thank you in advance :) the equation is in function of E and T.

i want to plot tauL=f(T) T is between 0 and 130 K T=[0 130] E become constant = 1.228eV

this a graph of tauL=f(T)

and i want to plot tauL=f(E)

E is between  1.2 and 1.26 eV 
and T become constant =10K

and the graph of tauL=f(E) must be like this

tauL =luminescence lifetime
Kb=8.61e-5
gammac=0.22
Ea=1.244e-3 eV
taur=0.342ns
tautr=0.129ns

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Answer 1

Quinten Rensen 2018-7-27

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在 MATLAB Online 中打开

I think there is something wrong with your units, but try something like this:
clear all, clc
Ec = 1.228e-3;
Tc = 10;
k=8.61e-5;
gamma=0.22;
Ea=1.244e-3;
Tau_r=0.342;
Tau_tr=0.129;
Tau_T = @(T) Tau_r ./ (1+(Tau_r./Tau_tr).*(1-gamma).*exp((Ec-Ea)./(k.*T)));
Tau_L = @(E) Tau_r ./ (1+(Tau_r./Tau_tr).*(1-gamma).*exp((E-Ea)./(k.*Tc)));
figure(1),clf(1)
fplot(Tau_T,[0,130])
xlabel('T(K)')
ylabel('Luminescence lifetime (ns)')
figure(2),clf(2)
fplot(Tau_L,[1.2e-3,1.26e-3])
xlabel('E(eV)')
ylabel('Luminescence lifetime (ns)')

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khouloud abiedh 2018-7-27

thank you very much for your answer. yes i add e-3 to Ea and Ec . Ea=1.244 eV and Ec=1.228eV.

khouloud abiedh 2018-7-30

hello i delete e-3 from Ec ,Ea and from the interval below but the figure which i find it is not similar to the real graphs

Ec = 1.228; Tc = 10; k=8.61e-5; gamma=0.220; Ea=1.244; Tau_r=0.342; Tau_tr=0.129; Tau_T = @(T) Tau_r ./ (1+(Tau_r./Tau_tr).*(1-gamma).*exp((Ec-Ea)./(k.*T))); Tau_L = @(E) Tau_r ./ (1+(Tau_r./Tau_tr).*(1-gamma).*exp((E-Ea)./(k.*Tc))); figure(1),clf(1) fplot(Tau_T,[0,130]) xlabel('T(K)') ylabel('Luminescence lifetime (ns)') figure(2),clf(2) fplot(Tau_L,[1.2,1.26]) xlabel('E(eV)') ylabel('Luminescence lifetime (ns)')

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