matching template with image

2012 6 16
2 个回答
3 次查看（30 天）

0 个投票

I = imread('man.bmp'); % Load initial figure
a = imcrop(I,[50 40 150 100]);
m=imrotate(a,180);
%(Convolution is equivalent to correlation if you rotate the convolution kernel by 180.) To match the template to the image, use the fft2 and ifft2 functions.
C = real(ifft2(fft2(I).* fft2(m(a,2),256,256)));
I'm getting this error: ??? Subscript indices must either be real positive integers or logicals.
how to fix it ????

请先登录，再回答此问题。

回答（2 个）

Walter Roberson
Walter Roberson 2012-6-16

0 个投票

You are trying to index your rotated image at your cropped image -- m(a,2)
I do not know what you intend that to mean.

5 个评论
显示 3更早的评论 隐藏 3更早的评论

lama riad
lama riad 2012-6-16
Locating Image Features.......http://www.mathworks.com/help/toolbox/images/f21-17064.html
actually coz my project is about image registration whatever I see related to it such as correlation I want to try it ....I have some problems in the code of registration I have I want to fix n add things; I tried n searched but no one is listening to me. I want to contact with some body to understand n encounter the problems
Walter Roberson
Walter Roberson 2012-6-16
In that code, C = real(ifft2(fft2(bw) .* fft2(rot90(a,2),256,256)));
rot90 is not a variable, it is a function with parameters "a" and "2". The effect of rot90(a,2) is to rotate "a" by 180 degrees, which sounds like what you want, so it is not obvious why you did the imrotate() by 180 -- rot90 would be faster. Anyhow, change your code to
C = real(ifft2(fft2(I).* fft2(m,256,256)));
Walter Roberson
Walter Roberson 2012-6-16
In the context of MATLAB Answers, "no one is listening" is usually because the regular volunteers do not happen to know anything about that field.
(I have tried answering people with "I do not know", in order to let them know that someone is listening but does not happen to have the answer, but the responses I received in return were less than appreciative.)
lama riad
lama riad 2012-6-16
pardon me I mean I was seeking for help in matlab from people not necessarily in mathworks only n no one is replying I donno why I'm not professional in matlab that's why I'm asking..... some people published their works in mathwork n since I ask them regarding such a point in their work they r not replying
lama riad
lama riad 2012-6-16
n thank u for the reply

请先登录，再进行评论。

Image Analyst
Image Analyst 2012-6-16

0 个投票

"a" is a matrix. So is "m" - in fact it is the rotated version of "a". So you cannot do m(a,2). The first index must be an integer number or array or a logical value or array. You cannot have a 2D or 3D matrix (an image) for an index. I haven't replied to anyone in the past 8 days because I was way out in the wilderness. I don't work for Mathworks, by the way.

类别

在 帮助中心 和 File Exchange 中查找有关 Read, Write, and Modify Image 的更多信息

标签

提问:

lama riad
lama riad
2012-6-16

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by