Initialize a field in all elements of a struct array
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Hi,
I'm looking for a "one-liner" for initialization of a certain field in an existing struct array. I know that I may achieve this by calling struct(somefiledname,values), or something similar) but I want to initialize all of these additional fields for an existing array of structs, without changing the existing fields.
For example- I have a(1).field1=1; a(2).field1=2; a(3).field1=3;
and I want a one-liner which will add an additional field- "field2" to the "a" struct array (possibly- all ones, all zeros etc.).
Any such shortcut? Or the only way is to iterate through the array?
Thanks!
采纳的回答
Simpler:
[a.field2] = deal(1);
Or if you have multiple items to use:
C = {1,2,3};
[a.field2] = C{:};
更多回答（2 个）
Try this out. It adds a field named 'field2' to each structure and allocates a vector of 4 zeros.
a = arrayfun(@(x) setfield(x, 'field2', zeros(1,4)), a);
James Tursa
2018-8-1
Another way using deal:
[a(1:numel(a)).field2] = deal(4);
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