How can I get subscript instead in indices from sort() ??
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How can I get subscript instead in indices from
sort(mat(:));
Script:
%%Creation of 'mat'
mat = magic(100);
for i=1:100*100
mat(mat>(100*i-100) & mat<=100*i)=i;
end
[~,idx] = sort(mat(:));
%%I dont want to use 'for' loop. I.e.,
for i=1:length(idx) % I want to avoid for loop
[I(i),J(i)] = ind2sub(size(mat),idx(i));
end
I tried 'arrayfun' also but it is taking more time then for loop
[I2,J2] = arrayfun(@(x) ind2sub(size(mat),x),idx);
1 个评论
Fangjun Jiang
2018-8-7
mat(:) turns mat() into a column vector. No point to get indices anyway.
采纳的回答
IND = [3 4 5 6]
s = [3,3];
[I,J] = ind2sub(s,IND)
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