Rearranging Bytes in a Cell

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So my output hexadecimal code is saved in a cell in the following format.
{'00 11 22 33 AA BB'}
I am trying to have it output as
{'1100 3322 BBAA'}
Any help would be greatly appreciated.

采纳的回答

Stephen23
Stephen23 2018-8-9
编辑:Stephen23 2018-8-9
This is easy with regexprep:
>> C = {'00 11 22 33 AA BB'};
>> regexprep(C,'(\w{2}) (\w{2})','$2$1')
ans =
'1100 3322 BBAA'

更多回答(1 个)

OCDER
OCDER 2018-8-9
A = {'00 11 22 33 AA BB'; '00 11 22 3D AA BC'; '02 11 32 33 AA BB'};
A = cellfun(@(x) sprintf('%c%c%c%c %c%c%c%c %c%c%c%c', strrep(x, ' ', '')), A, 'un', false);
A =
3×1 cell array
'0011 2233 AABB'
'0011 223D AABC'
'0211 3233 AABB'
  2 个评论
Stephen23
Stephen23 2018-8-9
Note that this does not return the order that the question requests.
OCDER
OCDER 2018-8-9
Doh, I didn't see that order change.

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