isa not recognizing Line or Figure class

2018 8 10
2 个回答
回答已采纳
更新时间：2018 8 10
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I wanted to test whether input data of a function is a Line object using something like:
>>
x=-2*pi:.01:2*pi;HLine=plot(sin(2*x));
However, now isa(HLine,'Line') returns false! So far, isa has faithfully recognized my self-made classes. Why doesn't it recognize Line?

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Guillaume
Guillaume 2018-8-10

1 个投票

>> x=-2*pi:.01:2*pi;HLine=plot(sin(2*x));
>> class(HLine)
ans =
'matlab.graphics.chart.primitive.Line'
>> isa(HLine, 'matlab.graphics.chart.primitive.Line')
ans =
logical
1
You need to use the fully qualified name of the class

更多回答（1 个）

KSSV
KSSV 2018-8-10

0 个投票

x=-2*pi:.01:2*pi;
HLine=plot(sin(2*x));
strcmp(HLine.Type,'line')

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Guillaume
Guillaume 2018-8-10
Note that the Type property of a graphics object is not relevant for isa.
KSSV
KSSV 2018-8-10
Yes....thats why I used strcmp to check is it a Line type.

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