relative error- can't stop it

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jamshid
jamshid 2011-3-28
[EDIT: 20110610 00:13 CDT - reformat - WDR]
Hi
I need help to write up a program which makes simple iterations. I don't know how to implement relative error and make it stop when error gets to 0.00001%.
here is my code:
%simple iteration method
f=input('f(x)=','s'); %you input the function, already re-arranged for calculations
tol='error tolerance=1e-5'; %error tolerance is defined by program
if length(tol)==0, tol=1e-5; end
x1=input('first guess=');
x=x1; fx=eval(f);
for i=1:1000000000
x=fx;
ff=eval(f);
fx=eval(f);
fprintf('i = %g, x = %g, fx = %g\n',i,x,fx)
end
Thank you for help

回答(1 个)

David Young
David Young 2011-3-28
To compute the relative error (assuming you're trying to find a stationary point of the function), after computing ff, subtract ff from x and take the absolute value. Then maybe you should divide that by the absolute value of x, but that depends on how you define relative error.
Then use a conditional statement (an "if" statement) to test whether the error is less than the tolerance, and use "break" to stop the loop if it is.
Other points to note:
  • 0.00001% is 1e-7, not 1e-5.
  • You can save computation time by using fx = ff instead of fx = eval(f). You do this after testing the error of course.
  1 个评论
jamshid
jamshid 2011-3-28
I tried to do it, but my error is not calculated with a new value of fx. so it always gets value of 0. then I tried to make condition if abs(fx)<tol, break, end but this doesn't execute the process. it just stops.

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