random exponential cdf numbers

2012 6 18
1 个回答
回答已采纳
6 次查看（30 天）

0 个投票

How could I generate random results from an exponential cumulative distribution function?
Thanks, in advance!

请先登录，再回答此问题。

 采纳的回答

bym
bym 2012-6-18

0 个投票

mu = 2 % mean of distribution
x = -mu*log(1-rand(1,10)); % ten numbers

2 个评论
显示 无 隐藏 无

evan lan
evan lan 2012-6-21
I thought it was the reverse type
mu = 2 % mean of distribution
p=1-exp(-rand(1,10)/mu);
Am I wrong?
bym
bym 2012-6-21
Well, yes you are. Please see http://en.wikipedia.org/wiki/Inverse_transform_sampling

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Random Number Generation 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by