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random exponential cdf numbers

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evan lan
evan lan 2012-6-18
How could I generate random results from an exponential cumulative distribution function?
Thanks, in advance!

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bym
bym 2012-6-18
mu = 2 % mean of distribution
x = -mu*log(1-rand(1,10)); % ten numbers
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evan lan
evan lan 2012-6-21
I thought it was the reverse type
mu = 2 % mean of distribution
p=1-exp(-rand(1,10)/mu);
Am I wrong?
bym
bym 2012-6-21
Well, yes you are. Please see http://en.wikipedia.org/wiki/Inverse_transform_sampling

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