Loop to carry out calculation for pairs 1 and 2, then pairs 2 and 3 and so on.

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BOB 2018-8-21

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评论： Torsten 2018-8-21

采纳的回答： Torsten

Hi,

I have two 8x1 matrices. One matrix is list of longitude coordinates (Final_Longitude_Values). The other matrix is the corresponding latitude coordinates (Final_Latitude_Values).

I want to calculate the distance between the first pair and the second pair, and then the second pair and the third pair, and so on until I have come to the end of each matrix.

I have written the following code in an attempt to automate this process:

{for j = 1:length(Final_Latitude_Values)

latlon1=[(Final_Latitude_Values(j)) (Final_Longitude_Values(j))];

latlon2=[(Final_Latitude_Values(j+1) (Final_Longitude_Values(j+1))];

end

[d1km d2km]=distance(latlon1,latlon2);

Segment_Distance = d2km}

However, the index exceeds the matrix dimensions, and I can't seem to figure out how to work around this issue. If anyone could correct my code it would be much appreciate.

Thanks

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Torsten 2018-8-21

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Use

for j = 1:length(Final_Latitude_Values)-1

instead of

for j = 1:length(Final_Latitude_Values)

Best wishes

Torsten.

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更多回答（2 个）

Fangjun Jiang 2018-8-21

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You have 8 locations thus 7 distances. When j is 8, Final_Latitude_Values(j+1) exceeds the matrix dimension.

Change the for-loop to

for j = 1:length(Final_Latitude_Values)-1

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BOB 2018-8-21

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Cheers folks! Works great.

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Torsten 2018-8-21

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I don't know if this is intended, but note that you only calculate the distance between the last two components of the vectors, namely

[(Final_Latitude_Values(j)) (Final_Longitude_Values(j))]

and

[(Final_Latitude_Values(j+1)) (Final_Longitude_Values(j+1))]

for

j = length(Final_Latitude_Values)-1.

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