Why would chol fail?
2 次查看(过去 30 天)
显示 更早的评论
I have a positive definite sparse array Ainv. When I do the chol like
L=chol(Ainv);
M = L*L';
isequal(M,Ainv)
I find that M is not equal to Ainv. How can I use chol to get a right answer?
0 个评论
采纳的回答
Stephan
2018-8-25
编辑:Stephan
2018-8-25
Hi,
L*L'
is not the same as
L'*L
You can test with this little example:
A = [7 3; 3 7]
ev = eig(A)
Ch = chol(A)
B1 = Ch'*Ch
B2 = Ch * Ch'
EDIT:
Is Ainv symmetric? If it is, consider that we are dealing with double precision numbers and the operations you perform have rounding errors. See this example:
A = [7 3; 3 7]
Ch = chol(A)
B1 = Ch' * Ch
same = isequal(A,B1)
diff = A-B1
B2 = round(Ch' * Ch)
same2 = isequal(A,B2)
diff2 = A-B2
So there is not a problem with chol, since this is a normal behavior.
Best regards
Stephan
更多回答(1 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Eigenvalue Problems 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!