index exceeds array bound meaning?

what is the meaning of index exceeds array bound

3 个评论

clc
clear
%Step 1: Define decision variables
x =optimvar('x',2,'LowerBound',[0 0],'UpperBound',[5 5]);
%Step 2: Define objective function
obj = x(1)^2 + x(2)^2 + x(3)^2;
%Step 3: Define constraints (if any)
A = 1 -x(2)^(-1)* x(3) >= 0;
B = x(1) - x(3) >=0;
C = x(1) - x(2)^2+x(2)*x(3)-4 ==0;
%Step 4: Define objective problem
prob = optimproblem('Objective',obj,'ObjectiveSense','maximize');
prob.Constraints.con_1 = A;
prob.Constraints.con_2 = B;
prob.Constraints.con_2 = C;
%Step 5: Solve the problem
x0.x = [0 0];
%Defining initial starting point
[sol, fval, exitflag, output] = solve(prob,x0);
kindly resolve this
You have
x =optimvar('x',2,'LowerBound',[0 0],'UpperBound',[5 5]);
so you say that x is a vector of 2 optimization variables. Your upper bound and lower bound are both vectors of length 2, which is consistent. x is not ambiguous: it really is length 2.
obj = x(1)^2 + x(2)^2 + x(3)^2;
but there you try to use x(3)^2 which would require that x be of length 3 or more.
Your constaints A, B, C all require that x has at least 3 elements.
x0.x = [0 0];
but that says that the initial value is a vector of length 2.
You need to decide whether your function involves 2 variables or 3 variables.

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 采纳的回答

It means that the index number is more than the array elements.
An example:
x=[1:10]
x(11)
Your array has 10 elements but you try accessing the 11th element.

9 个评论

For example, if you have a vector with 5 elements in it, and you ask to return the 6th element, then the 6 would be out of bounds in that case.
@Chaitanya lakeshri please let us know if something is unclear.
Got it Thank you for your
Got it Thank you for your help Madhan and walter
Sir if we are using like in the latest version, idx=1 and filename = files(idx);
the error occurs like this "Index exceeds array bounds."
here i used the same example and code from
openExample('nnet/ClassifyVideosUsingDeepLearningExample')
hmdb51Files() returned empty for you.
I suspect that you are not running R2019a .
Erro
Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in New_Arya_Paris (line 27)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
-------------------------------------------------------
Problm
w=[1.000 0.993 0.984 0.968 0.938 0.870 0.787 0.766 0.660 0.553 0.383 0.298 0.234 0.191 0.085]
d=[2.000 1.000 0.500 0.250 0.150 0.053 0.054 0.039 0.023 0.013 0.008 0.006 0.005 0.004 0.001]
di=d.*100
wi=(w.*1000)
ni=15
for j=1:1;
for i=1:(ni-1)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
end
end
You create a row vector, 1 row multiple columns. but index it as multiple rows with one column.

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更多回答(1 个)

Good morning,
I would like to obtain the real time of my computer to later carry out operations and obtain the elapsed time. I have used the "datetime" command but I can't separate the time from the date and use it for this purpose. Any suggestion? I would be very grateful

1 个评论

Most of the time, you would use tic and toc to obtain elapsed time.
You can also use
tin = clock;
do your code
tout = clock;
how_long = etime(tout, tin) %seconds
You can also
tin = datetime();
do your code
tout = datetime();
how_long = seconds(tout - tin) %seconds

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