index exceeds array bound meaning?

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Chaitanya Lakeshri
评论： Walter Roberson 2022-11-28
what is the meaning of index exceeds array bound
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Walter Roberson
Walter Roberson 2022-3-29
@suman sourabh
You have
x =optimvar('x',2,'LowerBound',[0 0],'UpperBound',[5 5]);
so you say that x is a vector of 2 optimization variables. Your upper bound and lower bound are both vectors of length 2, which is consistent. x is not ambiguous: it really is length 2.
obj = x(1)^2 + x(2)^2 + x(3)^2;
but there you try to use x(3)^2 which would require that x be of length 3 or more.
Your constaints A, B, C all require that x has at least 3 elements.
x0.x = [0 0];
but that says that the initial value is a vector of length 2.
You need to decide whether your function involves 2 variables or 3 variables.

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madhan ravi
madhan ravi 2018-9-2
编辑：madhan ravi 2018-9-2
It means that the index number is more than the array elements.
An example:
x=[1:10]
x(11)
Your array has 10 elements but you try accessing the 11th element.
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Umar Farooq
Umar Farooq 2022-11-28
Erro
Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in New_Arya_Paris (line 27)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
-------------------------------------------------------
Problm
w=[1.000 0.993 0.984 0.968 0.938 0.870 0.787 0.766 0.660 0.553 0.383 0.298 0.234 0.191 0.085]
d=[2.000 1.000 0.500 0.250 0.150 0.053 0.054 0.039 0.023 0.013 0.008 0.006 0.005 0.004 0.001]
di=d.*100
wi=(w.*1000)
ni=15
for j=1:1;
for i=1:(ni-1)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
end
end
Walter Roberson
Walter Roberson 2022-11-28
You create a row vector, 1 row multiple columns. but index it as multiple rows with one column.

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CECILIA ABASCAL FALAGAN
Good morning,
I would like to obtain the real time of my computer to later carry out operations and obtain the elapsed time. I have used the "datetime" command but I can't separate the time from the date and use it for this purpose. Any suggestion? I would be very grateful
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Walter Roberson
Walter Roberson 2020-8-16
Most of the time, you would use tic and toc to obtain elapsed time.
You can also use
tin = clock;
do your code
tout = clock;
how_long = etime(tout, tin) %seconds
You can also
tin = datetime();
do your code
tout = datetime();
how_long = seconds(tout - tin) %seconds

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