how to detect corner of image and find coordinate of corner - I need M-file code

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KURNIAWAN
KURNIAWAN 2012-6-21
评论： Image Analyst 2020-10-20
Please help , i had tried to find corner and coordinate of corner automatically,,, but still have problem to solve,, can u help me to make code-mfile,, i still confuse how to find corner and find coordinate automatically,, i have image tile square , how to detect 4 corner of tile ceramic and find value of coorninate 4 corner of tile ,
this link of image of tile : <http://tinypic.com/view.php?pic=2czer0o&s=6>
binary image of tile : <http://tinypic.com/view.php?pic=4q6gw4&s=6>
tile before croping and warping : <http://tinypic.com/view.php?pic=k4yyyd&s=6>

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回答（3 个）

Sean de Wolski
Sean de Wolski 2012-6-21
How about:
doc cornermetric
as a place to start?
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matlab_image
matlab_image 2012-6-21
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Walter Roberson
Walter Roberson 2012-6-21
Unfortunately we do not know if the poster is using a version of MATLAB new enough to have the "corner" routine. The poster was asked in one of the numerous threads the poster has started on this topic, but did not answer.
KURNIAWAN
KURNIAWAN 2012-6-21
i confuse with harris corner detector http://www.mathworks.com/matlabcentral/fileexchange/9272-harris-corner-detector/content/Harris.m
in m-file use imag.mat... how if i use image to process

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Image Analyst
Image Analyst 2012-6-21
I thought from your prior messages on this tile that you needed the corners to know how to warp the image. Now it looks like you're saying that you warped it somehow without the corners. But unfortunately you warped it incorrectly so that it's still not square.
But if it were the binary image, you could simply use find() in the first and last row of the binary image to find the corners.
upperLeftCornerX = find(binaryImage(1,:), 1, 'first');
upperRightCornerX = find(binaryImage(1,:), 1, 'last');
lowerLeftCornerX = find(binaryImage(end,:), 1, 'first');
lowerRightCornerX = find(binaryImage(end,:), 1, 'last');
but again, you must already have the corners to do that incorrect warping so why not just do it correctly, using the code I gave you in the other posting? There is no need to correct the skewness only part way and then try to warp it again to get it all the way fixed.
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