How to run a for loop n times with a different size matrix inside the loop

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BryanE
BryanE 2018-9-5
编辑： Koundinya 2018-9-11
I am attempting to run the four values of x_o and y_o through the loop to do conformal mapping. The matrix size of the circle in the loop is different, but I need to run it four times, with four different output graphs. Is this possible in MATLAB? Thanks
Here is what I have so far:
x_o = [0.1, 0.15, 0.2, 0.25]; y_o = [0.1, 0.15, 0.2, 0.25]; n = length(x_o);
for i = 1:n
R = 1;
theta = linspace(0,2*pi,100);
x = R*cos(theta) - x_o;
y = R*sin(theta) + y_o;
b = sqrt(R^2 - y_o.^2) + x_o;
A = x + [(x.*b.^2)./(x.^2 + y.^2)];
B = y - [(y.*b.^2)./(x.^2 + y.^2)];
figure
plot(x,y,'--',A,B)
grid on
end
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BryanE
BryanE 2018-9-5
My problem is that the matrix don't agree, is there a way to setup the loop to avoid this?
Stephen23
Stephen23 2018-9-5
"My problem is that the matrix don't agree"
Don't agree with what?
Please given an actual example of the inputs and outputs that you expect to get.

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Koundinya
Koundinya 2018-9-10
编辑：Koundinya 2018-9-11
You must be getting the error ' Matrix dimensions must agree ', this is because
theta = linspace(0,2*pi,100);
creates a vector theta with dimensions 1x100, R*cos(theta) and R*sin(theta) will also have dimensions equal to 1x100 , but your vector x_o is of dimension 1x4, so adding/subtracting vectors of unequal dimensions will result in an error
% Error occurs at these lines
x = R*cos(theta) - x_o;
y = R*sin(theta) + y_o;
b = sqrt(R^2 - y_o.^2) + x_o;
to iterate through each element of the vectors x_o and y_o, change it to
x = R*cos(theta) - x_o(i);
y = R*sin(theta) + y_o(i);
b = sqrt(R^2 - y_o(i).^2) + x_o(i);

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