EVAL do not display OUTPUT
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Hi all,
I am using eval function but even if I put semicolon ";" at the end of the line Matlab shows the output in the command window.
Is it possible to not display the result in the command window?
采纳的回答
"I am using eval function but"
Don't use eval. It's one of those functions that's there but not to be used unless absolutely necessary, which is almost never. eval creates very inefficient, hard-to-debug codes.
For your case, use fprintf or disp to display variables you want. Otherwise, use the ";" to silence the output.
A = rand(3) %creates and shows A
A = rand(3); %silenced output for A
disp(A); %shows A
I am guessing you did something like this:
eval('A = rand(3)'); %Does not silence output for A = rand(3)
eval('A = rand(3);') %Silences output A = rand(3). But why bother using eval???
5 个评论
Miroslav Mitev
2018-9-6
编辑：Miroslav Mitev
2018-9-6
@Miroslav Mitev: that is exactly what the MATLAB documentation recommends to avoid, and it also tells you what the preferred alternative its: "A frequent use of the eval function is to create sets of variables such as A1, A2, ..., An, but this approach does not use the array processing power of MATLAB and is not recommended. The preferred method is to store related data in a single array"
Simply use indexing to store your data in a single array, which might be numeric, cell, struct, table, etc. Indexing is very efficient, unlike what you are trying to do. Read more here:
Miroslav Mitev
2018-9-6
WinCento99
2020-11-2
编辑：WinCento99
2020-11-2
%% Initial structuring
y = [1 2] ;
f = @(y) [y bsxfun(@minus,sin(y(end)),y(end-1))] ;
%% Direct loop
for i = 1:19
y = f(y) ;
end
%% Loop with anonymous function --
% How can I have y after the loop with the true output?
fun = @(x) eval(['for i = 1:' num2str(x) '; y = f(y); end;']);
fun(19)
How can I have y after the loop with the true output?
Steven Lord
2020-11-2
What you've written will not work for a couple different reasons, the first of which is that it attempts to create the variable i in the anonymous function's workspace.
Not every piece of code is suitable for conversion into an anonymous function. I would define your fun as a regular old function.
function y = fun(f, y, x)
for iter = 1:x
y = f(y);
end
end
If you nested this inside the function where you wanted to call it, you could share f and y with that workspace and avoid having to pass them into fun.
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