how to solve this equastion : y''-1=exp(x) second order diff. equastion by use matlab command please reply

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RAJPUT JIGARSINH
RAJPUT JIGARSINH 2018-9-6
编辑： RAJPUT JIGARSINH 2018-9-6
how to solve this equastion : y''-1=exp(x) second order diff. equastion please reply
  1 个评论
Torsten
Torsten 2018-9-6
y'' = 1 + exp(x)
-> y' = x + exp(x) + a1
-> y = 1/2*x^2 + exp(x) + a1*x + a2
a1, a2 are arbitrary constants to be deduced from the initial/boundary conditions.
Best wishes
Torsten.

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回答（1 个）

Dimitris Kalogiros
Of course , Trosten gave the solution for this ODE, but maybe it worths to have a look on how we can use symbolic maths toolbox to handle these equations:
clear; clc;
syms x y(x)
syms a_0 a_1
Dy=diff(y,x) %definition of first derivative
ode=diff(y,x,2)-1==exp(x) % definition of 2nd order ODE
cond1=y(0)==a_0 % initial conditions
cond2=Dy(0)==a_1
ySol(x)=dsolve(ode, [cond1 cond2]) %solve ODE
And if someone run this script, will receive :

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