I need to check cell value along each diagonal. then if condition which I have define is satisfying, cells which have NaN value should replace by interpolation of cells beside NaN value cells.

Question

saumya jayasundara 2018-9-7

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/417968-i-need-to-check-cell-value-along-each-diagonal-then-if-condition-which-i-have-define-is-satisfying

编辑： KSSV 2018-9-7

for q=1:nBinsY-2    
    if q==1       
        for p=3:nBinsX
            s=p;
            for i = 1:s-1
                j = p;
                if ~isnan(minz(i,j)) && isnan(minz(i+1,j-1))
                    for jj=2:p-1
                        if ~isnan(minz(i+jj,j-jj))
                            dz=minz(i,j)-minz(i+jj,j-jj);
                            dx=minx(i,j)-minx(i+jj,j-jj);
                            dy=miny(i,j)-miny(i+jj,j-jj);
                            ddi=sqrt(square(dx)+square(dy));
                            if abs(dz)<1 && abs(ddi)<5
                                sl=dz/ddi;
                                ddx=dx/(jj);
                                ddy=dy/(jj);
                                  for r=1:jj-1
                                      minz(i+r,j-r)=minz(i,j)+(sl*r);
                                      minx(i+r,j-r)=minx(i,j)+(ddx*r);
                                      miny(i+r,j-r)=miny(i,j)+(ddy*r);
                                  end
                              else
                                  continue
                              end
                          else
                              continue
                          end
                          i=i+jj;
                          j=j-jj;
                      end
                  else
                      continue
                  end
                  p=p-1;
              end
          end
      else
          p=nBinsX
          for i = q:p+1
              j=p;
              if ~isnan(minz(i,j)) && isnan(minz(i+1,j-1))
                  for jj=2:p-1
                      if ~isnan(minz(i+jj,j-jj))
                          dz=minz(i,j)-minz(i+jj,j-jj);
                          dx=minx(i,j)-minx(i+jj,j-jj);
                          dy=miny(i,j)-miny(i+jj,j-jj);
                          ddi=sqrt(square(dx)+square(dy))
                          if abs(dz)<1 && abs(ddi)<5
                              sl=dz/ddi;
                              ddx=dx/(jj);
                              ddy=dy/(jj);
                              for r=1:jj-1
                                  minz(i+p,j-p)=minz(i,j)+(sl*r);
                                  minx(i+p,j-p)=minx(i,j)+(ddx*r);
                                  miny(i+p,j-p)=miny(i,j)+(ddy*r);
                              end
                          else
                              continue
                          end
                      else
                          continue
                      end
                      i=i+jj;
                      j=j-jj;
                  end
              else
                  continue
              end
              p = p-1;
          end
      end
  end